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1. A 0.338-g sample of antimony was completely reacted with 0.295 g of chlorine gas to form antimony chloride. Determine the empirical formula of the antimony chloride.

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Eduard22sly

The empirical formula of the antimony chloride is SbCl₃

Data obtained from the question

  • Antimony (Sb) = 0.338 g
  • Chlorine (Cl) = 0.295 g
  • Empirical formula =?

How to determine the empirical formula

Divide by their molar mass

Sb = 0.338 / 122 = 0.0028

Cl = 0.295 / 35.5 = 0.0083

Divide by the smallest

Sb = 0.0028 / 0.0028 = 1

Cl = 0.0083 / 0.0028 = 3

Thus, the empirical formula of the compound is SbCl₃

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