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Assuming ideal solution behavior, how many liters of hcl gas, measured at 30. 0 °c and 745 torr, are required to prepare 1. 25 l of a 3. 20-m solution of hydrochloric acid?.

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Eduard22sly

The volume of HCl gas required to prepare the solution is 101.54 L

How to determine the mole of HCl

  • Volume of solution = 1.25 L
  • Molarity = 3.20 M
  • Mole of HCl =?

Mole = Molarity x Volume

Mole of HCl = 3.2 × 1.25

Mole of HCl = 4 moles

How to determine the volume of HCl

  • Number of mole (n) = 4 moles
  • Temperature (T) = 30 °C = 30 + 273 = 303 K
  • Pressure (P) = 745 torr = 745 / 760 = 0.98 atm
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Volume =?

Using the ideal gas equation, the volume of the HCl gas can be obtained as follow:

PV = nRT

Divide both side by P

V = nRT / P

V = (4 × 0.0821 × 303) / 0.98

V = 101.54 L

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