megumihayashi0624200
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An acrobat on skis starts from rest 50.0 m above the
ground on a frictionless track and flies off the track
at a 45.0° angle above the horizontal and at a height
of 10.0 m. Disregard air resistance.
a. What is the skier's speed when leaving the
track?
b. What is the maximum height attained?

Respuesta :

onyebuchinnaji

The initial speed of the skier is 14 m/s.

The maximum height attained by the skier is 15 m.

Initial speed of the skier

The initial speed of the skier is determined by using the following kinematic equation.

[tex]K.E = mgh\\\\\frac{1}{2} mv^2 = mgh\\\\\frac{1}{2} v^2 = gh\\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2\times 9.8 \times 10} \\\\v = 14 \ m/s[/tex]

Maximum height attained

The maximum height attained by the skier is calculated as follows;

[tex]H = \frac{v^2 sin^2\theta}{2g} \\\\H = \frac{14^2 \times (sin45)^2}{2 \times 9.8} \\\\H = 5 \ m[/tex]

Thus, the maximum height attained by the skier is (10 + 5) = 15 m.

Learn more about maximum height of projectile here: https://brainly.com/question/12870645

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