what is the amount of energy associated with a photon that has a frequency of 1000 Hz?

Hi ! Here, I will help you to explain the material about photon energy. Photon energy is the energy carried by electromagnetic waves as they propagate. Photon energy is generally affected on frequency (the higher the frequency value, the energy will greater too) or wavelengths (the higher value of the wavelengths, the energy will smaller). So, based on the two concepts above, this is the following equation :

By the Frequency

[tex] \boxed{\sf{\bold{E = h \times f}}} [/tex]

By the Wavelengths

[tex] \boxed{\sf{\bold{E = h \times \frac{c}{\lambda}}}} [/tex]

With the following condition :

E = foton energy (J)
h = Planck constant ≈ [tex] \sf{6.626 \times 10^{-34} \: J.s} [/tex]
c = the constant of the speed of light in a vacuum ≈ [tex] \sf{3 \times 10^{8} \: m/s} [/tex] m/s
f = frequency of electromagnetic wave (Hz)
[tex] \sf{\lambda} [/tex] = wavelength (m)

Problem Solving

We know that :

h = Planck constant ≈ [tex] \sf{6.626 \times 10^{-34} \: J.s} [/tex]
f = frequency of electromagnetic wave = 1,000 Hz = 10³ Hz.

What was asked :

E = foton energy = ... J

Step by step :

[tex] \sf{E = h \times f} [/tex]

[tex] \sf{E = 6.626 \times 10^{-34} \times 10^3} [/tex]

[tex] \boxed{\sf{E = 6.626 \times 10^{-31} \: J}} [/tex]

Conclusion

So, the amount of energy associated with a photon that has a frequency of 1000 Hz is [tex] \sf{6.626 \times 10^{-31} \: J} [/tex]