What is the slope of the line that passes through the points (6,-5) and (6,-4)?
Write your answer in simplest form.

Answer:
[tex] \boxed{\tt \: m = \boxed{\tt Undefined}}[/tex]
Step-by-step explanation:
Given Two Points are:
[tex] \sf \: \tt (6,-5) \: \sf and \: \tt (6,-4)[/tex]
We need to Find:
[tex] \longrightarrow \sf \: The \: Slope[/tex]
We know that,
[tex] \sf \: Slope = \tt \: Rise/Run \: , \: \sf \: i.e. \: \: \boxed{\tt\dfrac{y_2-y_1}{x_2-x_1}}[/tex]
[tex] \sf \: Slope= \boxed{\tt\dfrac{y_2-y_1}{x_2-x_1}}[/tex]
Where,
[tex] \tt \: y_2= -4[/tex]
[tex]\tt y_1= - 5[/tex]
[tex]\tt x_2=6[/tex]
[tex] \tt \: x_1=6[/tex]
So Substitute their values accordingly:
[Important Note: Slope is denoted as m generally.]
[tex] \tt\implies \: m = \cfrac{ - 4 -( - 5)}{6 - 6} [/tex]
Now Simplify it.[Follow BODMAS Rule strictly while simplifying]
[tex] \tt \implies m = \cfrac{ - 4 + 5}{0} [/tex]
[tex]\tt \implies m = \cfrac{ 1}{0} [/tex]
Here, We can find that 1 is divided by 0.
We know that any expressions divided by 0 is undefined .
Hence, the slope[m] would be undefined.
[tex] \rule{225pt}{2pt}[/tex]
I hope this helps!
Let me know if you have any questions! :)