Mxiin7
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A block of aluminum measures 4.0 cm x 5.0 cm x 2.0 cm is completely immersed in a tank of water.
Calculate the buoyant force and the mass of the displaced water (Remember the density of water is 1 g/mL) (g=10m/s2)

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SonamDendup123

Answer:

upthrust or BUOYANT FORCE =Vdg

volume=LWH

upthrust=(4cm×5cm×2cm)×1g/cm²×g

upthrust=40cm³×1g/cm³×g

upthrust=40gf or 0.04kg×10m/s²=0.4N

weight of the displaced liquid is upthrust.

so mass=40g or 0.04kg

upthrust=40gf or 0.4Nand mass of the displaced liquid=40g or 0.04kg

please mark brainliest, hope it helped

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