Answer:
vertex = (- 3, 1 )
Step-by-step explanation:
given a quadratic in standard form
f(x) = ax² + bx + c ( a ≠ 0 )
then the x- coordinate of the vertex is
x = - [tex]\frac{b}{2a}[/tex]
f(x) = x² + 6x + 10 ← is in standard form
with a = 1, b = 6 , then
x = - [tex]\frac{6}{2}[/tex] = - 3
substitute x = - 3 into f(x) for corresponding y- coordinate
f(- 3) = (- 3)² + 6(- 3) + 10 = 9 - 18 + 10 = 1
vertex = (- 3, 1 )
