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In a mixture of 3 gases what is the total pressure of the gases if Gas A exerts a pressure
of 400 mmHg, Gas B exerts a pressure of 220 mmHg and Gas C exerts a pressure of 140
mm Hg?

Respuesta :

VirαtKσhli

Answer:

760 mm of Hg

Explanation:

If the gases A , B and C are non reacting , then according to Dalton's Law of Partial Pressure the total pressure exerted is equal to sum of individual partial pressure of the gases .

If there are n , number of gases then ,

[tex] P_{total}= P_1+P_2+P_3+\dots +P_n[/tex]

Here ,

  • Partial pressure of Gas A = 400mm of Hg
  • Partial pressure of Gas B = 220 mm of Hg
  • Partial pressure of Gas C = 140mm of Hg

Hence the total pressure exerted is ,

[tex] P_{total}= P_{Gas\ A }+P_{Gas\ B }+P_{Gas\ C }[/tex]

Substitute ,

[tex]P_{total}=( 400 + 220 + 140 )mm\ of \ Hg [/tex]

Add ,

[tex]P_{total}= 760\ mm\ of \ Hg[/tex]

Hence the total pressure exerted by the gases is 760 mm of Hg.

I hope this helps.

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