Respuesta :

VirαtKσhli

Answer:

0.66 L

Explanation:

Here it's given that a sample of Neon occupies a volume of 0.220 L at 0.86 atm . And we need to find out its volume at 29.4 kPa .

If we assume temperature to be constant , then we can apply Boyle's Law , which states that ,

" For a fixed amount of gas at constant temperature , pressure is inversely proportional to the volume . "

Mathematically ,

[tex] P \propto \dfrac{1}{V}[/tex]

Taking k as constant ,

[tex] P =\dfrac{k}{V}[/tex]

And we can say that ,

[tex] P_1 V_1 = P_2V_2[/tex]

Here ,

  • P_1 = 0.87 atm
  • P_2 = 29.4 kPa = 29400 Pa

As we know that ,

[tex] 0.987 atm = 10^5\ Pa [/tex]

So ,

[tex] 29400 Pa = 0.29 \ atm [/tex]

  • V_1 = 0.220 L
  • V_2 = ?

So that ,

[tex] (0.87 atm )(0.220L) = (0.29atm)(V_2)\\[/tex]

[tex] V_2 = \dfrac{0.87 \times 0.220}{0.29} L [/tex]

Simplify ,

[tex] V_2 = 0.66\ L [/tex]

Hence the new Volume of the gas is 0.66 L .

I hope this helps.

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