Factors of a polynomial can divide it without leaving remainder. The other factor of [tex]6x^2 - 7x + 2[/tex] is given by Option D : [tex]3x + 2[/tex]
Let the polynomial A(x) has one factor f(x).
Then, it means, we have:
[tex]\dfrac{A(x)}{f(x)} = g(x)[/tex]
Thus, A(x) can be written as [tex]A(x) = f(x) \times g(x)[/tex]
Thus, the other factor of that polynomial is
[tex]g(x) = \dfrac{A(x)}{f(x)}[/tex]
For given case, the polynomial [tex]A(x)[/tex] is
[tex]A(x) = 6x^2 - 7x + 2[/tex]
Its one factor f(x) is given [tex]f(x) = 2x - 1[/tex]
Thus, its second factor is obtained as:
[tex]g(x) = \dfrac{A(x)}{f(x)} = \dfrac{6x^2 - 7x + 2}{(2x - 1)} = \dfrac{6x^2 -4x -3x - 2}{2x - 1}\\\\g(x) = \dfrac{2x(3x + 2) - 1(3x + 2)}{2x - 1} = \dfrac{(2x - 1)(3x + 2)}{2x - 1}\\\\g(x) = (3x + 2)[/tex]
Thus, the second factor of the given polynomial is
Option D : [tex]3x + 2[/tex]
Learn more about factors of polynomials here:
https://brainly.com/question/16078564