Answer:
Explanation:
Balanced Chemical Equation:
Cu + 2 AgNO₃ → Cu(NO₃)₂ + 2 Ag
Step 1: Find Limiting Reagent
Moles of Cu:
Mole = 3 g / 63.55 g/mol = 0.04721 mol
Moles of AgNO₃:
Moles = 3.85 g / 169.87 g/mol = 0.022664 mol
Also, Mole ratio of Cu : AgNO₃ is 1 : 2. Hence, 0.04721 mol of Cu will require 0.09442 mol of AgNO₃. This means, AgNO₃ is the limiting reagent.
Step 2: Calculate moles of Ag:
0.022664 mol of AgNO₃ will produce 0.022664 mol of Ag because both have same ratio in balanced chemical equation.
Step 3: Calculate mass of Ag:
Mass = 0.022664 mol × 107.87 g/mol = 2.4447 g
