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A cone-shaped tent has a diameter of 12 ft and a height of 6 ft. What is the approximate volume of the tent? Use 3. 14 to approximate pi, and express your final answer as a decimal. Enter your answer as a decimal in the box. Ft³.

Respuesta :

semsee45

Answer:

226.08 ft³

Step-by-step explanation:

[tex]\textsf{volume of a cone}=\frac{1}{3}\pi r^2h[/tex]
(where [tex]r[/tex] = radius of the base and [tex]h[/tex] = height)

[tex]\textsf{radius}\ r=\frac{1}{2}\ \textsf{diameter}[/tex]

Given:

  • diameter = 12ft  ⇒  radius = 12 ÷ 2 = 6 ft
  • height = 6ft
  • [tex]\pi[/tex] ≈ 3.14

[tex]\implies \textsf{volume of tent}=\frac{1}{3}\times3.14 \times 6^2 \times 6=226.08 \ \textsf{ft}^3[/tex]

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