During, an Experiment, The temperature of a solution changes from 9 4/5 F to 17 1/4 F.
What is the percent of increase in the temperature of the solution?
Enter your answer in the box as a percent rounded to the nearest hundredth

During an Experiment The temperature of a solution changes from 9 45 F to 17 14 F What is the percent of increase in the temperature of the solution Enter your class=

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Using improper fractions, it is found that the percent of increase in the temperature of the solution was of 76.08%.

How to convert improper fractions to standard fractions?

The conversion is made according to the following formula:

[tex]a\frac{b}{c} = a + \frac{b}{c} = \frac{ac + b}{c}[/tex]

In this problem, the initial temperature was given by:

[tex]9\frac{4}{5} = 9 + \frac{4}{5} = 9.8[/tex]

The final temperature was given by:

[tex]17\frac{1}{4} = 17 + \frac{1}{4} = 17.25[/tex]

What is the percent change?

The percent change is given by the change divided by the initial temperature, and multiplied by 100%. Hence:

[tex]C = \frac{17.25 - 9.8}{9.8} \times 100\% = 76.02\%[/tex]

To learn more about improper fractions, you can take a look at https://brainly.com/question/24606703