Answer:
here's an example of one assignment it might help you
Explanation:
54827 J energy will required to increase the temperature from 22.8°C to 94.6°C
We have given mass of aluminium m = 900 J/gram°C
Mass of the aluminium m = 850 gram
The temperature of the aluminium is increases from 22.8°C to 94.6°C
So increase in temperature \Delta TΔT = 94.6 - 22.8 = 71.8°C
We have to fond the energy required to raise the temperature
We know that energy is given by Q=mc\Delta TQ=mcΔT , here m is mass, c is specific heat and \Delta TΔT is increase in temperature
So energy Q=850\times 0.9\times 71.8=54827JQ=850×0.9×71.8=54827J
So 54827 J energy will required to increase the temperature from 22.8°C to 94.6°C