Your parents invest $10,000 in a college fund when you are born. They find a fund that will return 8% per year for 18 years.
When you are 18 you find a school that charges $12,000 tuition per year. Tuition increases at a rate of 11% per year (so the second year will have a tuition of $13,320) , will this money take care of four years of school? How many years of college will this take care of? Explain your answer fully.

Respuesta :

The interest is compounded in the investment and the fees, the 4 years

school fees is however larger than the future value of the investment.

Response:

  • The money is less required to take care of four years of school
  • Two years

How can the future value of the amount invested be found?

First part:

The future value, FV, of the investment after 18 years is given as follows;

  • [tex]FV = \mathbf{PV \cdot (1 + i)^n}[/tex]

Where;

PV = The present value = $10,000

i = The interest rate = 8% = 0.08

n = The number of years = 18

Which gives;

[tex]FV = 10,000 \times (1 + 0.08)^{18} \approx \mathbf{39,960.195}[/tex]

The future value of the investment, FV = $39,960.195

The school fees each year is given as follows;

Fees = First year fees·(1 + r)ⁿ

Where;

First year fees = $12,000

r = Increase rate of the school fees = 11% = 0.11

n = The number of years

The school fees for four years is given as follows;

∑Fees = $12,000 + $12,000·(1 + 0.11) + $12,000·(1.011)² + $12,000·(1.011)³

Which gives;

∑Fees = 12,000 + 12,000·(1 + 0.11) + 12,000·(1 + 0.11)² +12,000·(1 + 0.11)³ = 56,516.772

The total tuition fees for four years = $56,516.772

The future value of the investment after 18 years, $39,960.195 is less

than the amount required as school fees for four years, therefore;

  • The money is less than the amount to take care of four years of school

Second part:

The fees for 3 years of school is given as follows;

[tex]\displaystyle \sum \limits_{n = 1 }^3[/tex] = 12,000 + 12,000·(1 + 0.11) + 12,000·(1 + 0.11)² = 40,105.2 > 39,960.195

The fees for 2 years of school is given as follows;

[tex]\displaystyle \sum \limits_{n = 1 }^2[/tex] = 12,000 + 12,000·(1 + 0.11) = 25,320 < 39,960.195

The number of years of college the value of the investment will take care of is therefore;

  • Two years

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