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Two diodes are in series. The first diode has a voltage of 0.75 V and the second has a voltage of 0.8 V. If the current through the first diode is 400 mA, then the current through the second diode is _____ mA.

Respuesta :

The current in the second diode is 400mA

Data;

  • First Voltage = 0.75V
  • Second Voltage = 0.8V
  • First Current (I) = 400mA
  • Second Current(I) = ?

Current In a Series

The current in the first diode is equal to 400mA. In a series circuit, the current passing the diodes are equal. This implies that the current in the series are equal.

Diodes connected in series will be the equal.

[tex]I_1 = I_2[/tex]

Since I1 is 400mA, I2 will be equal to 400mA

[tex]I_1 = I_2\\I_1 = 400mA\\I_2 = 400mA[/tex]

The current in the second diode is 400mA

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