How could you use coordinate geometry to prove that BC=AD

Answer:
Step-by-step explanation:
To prove BC = AD just measure the length of each segment:
Correct choice is C
Find distances
[tex]\\ \tt\longmapsto BC=\sqrt{(6-0)^2+(6-6)^2}=\sqrt{6^2}=6[/tex]
[tex]\\ \tt\longmapsto AD=\sqrt{(3+3)^2+(2-2)^2}=\sqrt{6^2}=6[/tex]
Hence proved