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Select the correct answer. A mixture consists of glucose and water. What is the percent composition of glucose in the mixture if it contains 1. 3 moles of glucose (C6H12O6) and the total mass of the mixture is 276 grams? A. 17. 7% B. 26% C. 35% D. 77% E. 85%.

Respuesta :

haileyelder24

Answer:

The  percent composition of glucose  in the  mixture  is 85 % (Answer E)

Explanation:

"percent  composition of glucose = (mass of glucose /  mass  of the mixture) x 100

Step 1:  calculate the mass  of glucose ( C6H12O6)

mass of glucose =  moles of glucose  x  molar mass  of glucose

molar  mass of C6H12O6  = [( 12 x6) + ( 1  x12) + ( 16 x6)= 180 g/mol

mass  is therefore= 1.3 moles x 180g/mol = 234  grams

Step 2: calculate  the percent composition

= mass of glucose /mass of mixture x 100

= 234 g/276 g  x 100  = 85 %(answer E)"

Answer: the answer is E

Explanation: plato users

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