So, the frequency of that light approximately [tex] \sf{\bold{3.53 \times 10^{14} \: Hz}} [/tex]
Hi ! I will help you to explain the relationship between velocity of electromagnetic waves in a vacuum with frequency and wavelength. We all know that all of the type of electromagnetic wave, will have the same velocity as the speed of light (because the value is a constant), which is 300,000 km/s or [tex] \sf{3 \times 10^8} [/tex] m/s. As a result of this constant property, the shorter the wavelength, the greater the value of the electromagnetic wave frequency. This relationship can also be expressed in this equation:
[tex] \boxed{\sf{\bold{c = \lambda \times f}}} [/tex]
With the following condition :
We know that :
What was asked :
Step by step :
[tex] \sf{c = \lambda \times f} [/tex]
[tex] \sf{3 \times 10^8 = 8.5 \times 10^{-7} \times f} [/tex]
[tex] \sf{f = \frac{3 \times 10^8}{8.5 \times 10^{-7}}} [/tex]
[tex] \sf{f \approx 0.353 \times 10^{8 -(-7)}}} [/tex]
[tex] \sf{f \approx 3.53 \times 10^{-1} \times 10^{15}} [/tex]
[tex] \boxed{\sf{f \approx 3.53 \times 10^{14} \: Hz}} [/tex]
So, the frequency of that light approximately [tex] \sf{\bold{3.53 \times 10^{14} \: Hz}} [/tex]
