Using the binomial distribution, it is found that there is a 0.6836 = 68.36% probability that she guesses at least one right.
For each question, there are only two possible outcomes, either she gets it right or she does not get it right. The probability of getting a question right is independent of any other question, hence the binomial distribution is used to solve this question.
The formula is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
In this problem:
The probability that she guesses at least one right is:
[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]
In which:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{4,0}.(0.25)^{0}.(0.75)^{4} = 0.3164[/tex]
Hence:
[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.3164 = 0.6836[/tex]
0.6836 = 68.36% probability that she guesses at least one right.
You can learn more about the binomial distribution at https://brainly.com/question/24863377