Linear functions are functions that change at a constant rate
The linear function that models the data is [tex]P(x) = 0.025x -49.695[/tex]
From the question, we have the following ordered pairs
(x,P(x)) = (2005,43%) and (2011,58%)
Start by calculating the slope (m)
[tex]m = \frac{P(x2) - P(x1)}{x_2 -x_1}[/tex]
So, we have:
[tex]m = \frac{58\% - 43\%}{2011 - 2005}[/tex]
Evaluate the differences
[tex]m = \frac{15\%}{6}[/tex]
Evaluate the quotient
[tex]m = 2.5\%[/tex]
The linear function is then calculated as:
[tex]P(x) = m(x - x_1)+ P(x_1)[/tex]
So, we have:
[tex]P(x) = 2.5\%(x - 2005) + 43\%[/tex]
Rewrite as:
[tex]P(x) = 0.025(x - 2005) + 0.43[/tex]
This gives
[tex]P(x) = 0.025x -50.125 + 0.43[/tex]
[tex]P(x) = 0.025x -49.695[/tex]
Hence, the linear function that models the data is [tex]P(x) = 0.025x -49.695[/tex]
Read more about linear functions at:
https://brainly.com/question/15602982