Answer:
255 [m].
Explanation:
1) the formula is (d - requred distance, V₀ - initial velocity, t - elapsed time, a - deceleration):
[tex]d=V_0t+\frac{at^2}{2};[/tex]
2) according to the formula above the required distance is:
d=10*30-0.5*0.1*900=300-45=255 [m].
Apply second equation of kinematics
[tex]\\ \tt\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]
[tex]\\ \tt\longmapsto s=10(30)+\dfrac{1}{2}(-0.1)(30)^2[/tex]
[tex]\\ \tt\longmapsto s=300+(-0.1)(450)[/tex]
[tex]\\ \tt\longmapsto s=300-45[/tex]
[tex]\\ \tt\longmapsto s=255m[/tex]
