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The function f(x) = -(x+4)^2+5 is written in vertex form and shows that the vertex of the graph of f is located at (-4,5)
Each value of the f can be obtained from two different x-values except f(x)=5. Which best explains why f(x)=5 is the output for only one input value?

The function fx x425 is written in vertex form and shows that the vertex of the graph of f is located at 45 Each value of the f can be obtained from two differe class=

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abidemiokin

There is only one value for x that makes [tex](x+4)^2=0[/tex]

Vertex form of an expression

Given the vertex form of the function expressed as:

[tex]f(x) = -(x+4)^2+5[/tex]

If the function f(x) = 5

[tex]5 = -(x+4)^2+5[/tex]


Subtract 5 from both sides

[tex]5 = -(x+4)^2+5\\-(x+4)^2= 5-5\\-(x+4)^2=0\\[/tex]

Hence there is only one value for x that makes [tex](x+4)^2=0[/tex]

Learn more on vertex form here; https://brainly.com/question/525947

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