Answer:
0.3 moles of H2 will be produced.
Explanation:
Balanced reaction: 2 Al + 6 HCl → 2 AlCl3 + 3 H2
Given Al mass = 5.4 g, we know Mr of Al is 27
Using the formula:
moles = mass / Mr
moles of Al = 5.4 / 27
moles of Al = 0.2 moles
Here we see that "2" molar mass before Al; so in this reaction, "1" molar mass will have [(0.2)/2] = 0.1 moles. He see "3" molar mass before H2, therefore moles of H2 is (3 * 0.1) = 0.3 moles.
Balanced chemical equation is given by
[tex]\\ \tt\hookrightarrow 2Al+HCl\longrightarrow 2AlCl_3+3H_2[/tex]
Moles of Al:-
[tex]\\ \tt\hookrightarrow 5.4/27=0.2mol[/tex]
Now
