Trisha had the following seven distances (in feet) in the triple jump.

29, 30, 28, 32, 28, 31, 27

What was the interquartile range of her distances?

1
2
5
3

Respuesta :

Answer:

5 is your answer sweetheart

Step-by-step explanation:

We know that the range to a data set is the difference between the maximum data value and the minimum data value .

The given data set :  29, 30, 28, 32, 28, 31, 27

Maximum value = 32

Minimum value = 27

Then , the range the given data set would be :-

\begin{gathered}\text{Range = Maximum-Minimum}\\\\\Rightarrow\text{Range}=32-27=5\end{gathered}Range = Maximum-Minimum⇒Range=32−27=5

Hence, the range of her distances = 5

Answer:

5

Step-by-step explanation: