The uncertainty in the position of the proton is 1.1 x 10⁻¹³ m.
The velocity of the proton is calculated as follows;
[tex]v = \frac{1}{10} \times 3\times 10^8 \ m/s = 3 \times 10^7 \ m/s[/tex]
precision of the velocity, Δv = 0.01 x 3 x 10⁷ = 3 x 10⁵ m/s
The uncertainty in the position of the proton is calculated as follows;
[tex]\Delta xm\Delta v= \frac{h}{4\pi} \\\\\Delta x = \frac{h}{4\pi m\Delta v} \\\\\Delta x = \frac{6.67 \times 10^{-34} }{4\pi \times 1.67 \times 10^{-27} \times 3\times 10^5} \\\\\Delta x = 1.1 \times 10^{-13} \ m[/tex]
Thus, the uncertainty in the position of the proton is 1.1 x 10⁻¹³ m.
Learn more about uncertainty here: https://brainly.com/question/1970053
