The percentage of the total energy contributed by fat = 51.59% of fat
The quantity of fat in the hamburger = 36grams
But 1 gram of fat = 9 kcal( standard energy value per gram of fat).
That is , 9kcal = 1 gram
X kcal = 36 grams
cross multiply,
X kcal = 9 × 36
= 324kcal
To calculate the percentage of 324kcal of fat in 628 kcal,
[tex]\% = \frac{324}{628} \times \frac{100}{1} [/tex]
[tex]\% = \frac{32400}{628} [/tex]
% = 51.59% of fat
The percentage of the total energy contributed by fat = 51.59%
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