The radius of each jawbreaker is approximately 0.68 cm.
where
r = radius
Therefore,
23 g = 32.3 cm³
0.94 g = ?
cross multiply
volume of a single jawbreaker = 32.3 × 0.94 / 23 = 30.362 / 23 = 1.32 cm³
Therefore,
volume of each jawbreaker = 4 /3 πr³
1.32 = 4 / 3 × 3.14 × r³
r³ = 1.32 /4.18666666667
r³ = 0.31533683707
r = ∛0.31533683707
r = 0.680651651 = 0.68
Therefore, the radius of each jawbreaker is approximately 0.68 cm.
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