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** HELP ASAP!! **write an equation in slope intercept form of the line parallel to the graph of 9x+3y=6 that passes through (5,3)

Respuesta :

Lets find out,

The slope parallel to 9x+3y=6:-

[tex]m = - 3[/tex]

Substituting,

[tex]m = - 3 \\ x = 5 \: \: \: into \\ y = 3[/tex]

So,

[tex]y = mx + b[/tex]

[tex] = > 3 = - 3 \times 5 + b[/tex]

[tex] = > 3 = - 15 + b[/tex]

[tex] = > 3 + 15 = b[/tex]

[tex] = > 18 = b[/tex]

Substitute,

[tex]m = - 3 \\ b = 18[/tex]

Use,

[tex]y = mx + b[/tex]

[tex] = > y = - 3x + 18[/tex]

Now rewrite y= -3x+18 in slope intercept form,

(Please check the image attached for it)

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