Q(1)
a² + b² = c²
5² + 1² = (√26)²
25 + 1 = 26
26 = 26
Hence LHS = RHS proved, the triangle is a right angle triangle.
Q(2)
distance formula: [tex]\boxed{\sqrt{(x2- x1 )^2 + (y2 - y1 )^2}}[/tex]
using the formula:
[tex]\sqrt{(4- 2 )^2 + (-1 - 3 )^2}[/tex]
[tex]\sqrt{4+16}[/tex]
[tex]2\sqrt{5}[/tex] ____this is the distance between two points/coordinates.
Q(3)
c² = a² + b²
x² = 7² + 24²
x² = 49 + 576
x² = 625
x = √625
x = 25
[ here the mistake was they took 7 and 24 in the bracket by keeping square outside and added inside both which must and cannot be done ]
