Using compound interest, it is found that a sum of $16,586.26 must be deposited.
The amount of money earned, in compound interest, after t years, is given by:
[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]
In which:
In this problem:
The amount deposited is the principal, hence:
[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]
[tex]30000 = P\left(1 + \frac{0.09}{4}\right)^{4(6)}[/tex]
[tex](1.025)^{24}P = 30000[/tex]
[tex]P = \frac{30000}{(1.025)^{24}}[/tex]
[tex]P = 16586.26[/tex]
A sum of $16,586.26 must be deposited.
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