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AT constant temperature, a gas is compressed from 5.5 L to 1 L. At 1 L, the pressure of the gas is 98.2 kPa. What was the original pressure of this gas? (Use Boyle's Law)

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okpalawalter8

We have that  the original pressure of this gas  is mathematically given as

P2=17.854 kPa

Boyle's law

Question Parameters:

AT constant temperature, a gas is compressed from 5.5 L to 1 L.

At 1 L, the pressure of the gas is 98.2 kPa

Generally the equation for Boyle's law   is mathematically given as

P1V1=P2V2

Therefore

[tex]P1=\frac{P2V2}{V1}\\\\P2=\frac{98.2*1}{5.5}[/tex]

P2=17.854 kPa

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