Please answer. In parallelogram WXYZ, diagonals WY and XZ intersect at point A. Give WA=x^2-48 and AY=x^2-6x. What is WY? Show your work

The diagonals of a parallelogram are congruent
The length WY is 32
Given that:
[tex]WA = x^2 - 48[/tex] and
[tex]AY = x^2 - 6x[/tex]
Then, we have:
[tex]x^2 - 48 = x^2 - 6x[/tex]diagonal
Subtract x^2 from both sides
[tex]- 48 =- 6x[/tex]
Divide both sides by -6
[tex]x = 8[/tex]
The length WY is calculated as:
[tex]WY=2 * WA[/tex]
So, we have:
[tex]WY=2 * [x^2 - 48][/tex]
Substitute 8 for x
[tex]WY=2 * [8^2 - 48][/tex]
Simplify
[tex]WY=32[/tex]
Hence, the length WY is 32
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