As per the problem, the charge is of 2.5μC, moving in magnetic field [tex]3\times10^{2}[/tex] T and having velocity [tex]5\times 10^{3}[/tex] m/s, the force comes out to be 3.75N
Magnetic force is the force experienced by the object inside the magnetic field or flowing current across the conductor. This force is caused due to the movement of charges.
The force exerted is magnetic force which is given as,
[tex]F= QVBsin\theta[/tex]
here,
Q= charge
v= velocity
B= Magnetic field and
[tex]\theta[/tex]=Angle of object from magnetic field
[tex]F=2.5\times10^{-6} \times 5\times10^{3} \times3\times10^{2}\times sin90[/tex]
[tex]F=3.75N[/tex]
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