The change in temperature with the addition of Ar to He gas is 68.61 K. The negative change indicates the lowering of the temperature of gas.
The pressure of an ideal gas is given by the ideal gas equation as:
PV=nRT
The initial temperature of He gas is given as:
Substituting the values for initial temperature, [tex]T_i[/tex]:
[tex]T_i=\rm \dfrac{1.83\;atm\;\times\;2.50\;L}{0.458\;mol\;\times\;0.082\;J/mol.K} \\\textit T_\textit i=122\;K[/tex]
The initial temperature of the gas is 122 K.
The addition of 0.713 mol Ar, results in the final values of:
Substituting the values for final temperature, [tex]T_f[/tex]:
[tex]T_f=\rm \dfrac{2.05\;atm\;\times\;2.50\;L}{1.171\;mol\;\times\;0.082\;J/mol.K} \\\textit T_\textit f=53.3\;K[/tex]
The final temperature of the gas is 53.3 K.
The change in temperature ([tex]\Delta T[/tex]) is given as:
[tex]\Delta T=T_f-T_i\\\Delta T=53.3-122\;\text K\\\Delta T=-68.61\;\text K[/tex]
The change in temperature of the gas is 68.61 K. The negative sign indicates the lowering of temperature with the addition of Ar.
Learn more about ideal gas, here:
https://brainly.com/question/8711877
