Respuesta :

fieryanswererft

Answer:

[tex]n = 3\sqrt{2}[/tex]

There are two best ways to solve this.

using cosine method:

[tex]cos(n) = \frac{adjacent}{hypotenuse}[/tex]

[tex]cos(60) = \frac{adjacent}{6\sqrt{2} }[/tex]

[tex]adjacent,n = cos(60) * 6\sqrt{2}[/tex]

[tex]n = 3\sqrt{2}[/tex]

using sine method:

[tex]sin(n) = \frac{opposite}{hypotenuse}[/tex]

[tex]sin(30)= \frac{n}{6\sqrt{2} }[/tex]

[tex]n = sin(30) * 6\sqrt{2}[/tex]

[tex]n = 3\sqrt{2}[/tex]

There are many ways, not to make it complex, these are the best ways to solve for n. Hope it helps ~

semsee45

Answer:

n = 3√2

Step-by-step explanation:

A 30-60-90 triangle is a special type of triangle as the measures of the sides are x, x√3, and 2x

i.e. the hypotenuse is twice the length of the shorter leg, and the length of the longer leg is √3 times the length of the shorter leg.

We have been given the length of the hypotenuse, so we can find the value of x:

⇒  2x = 6√2

⇒  x = 3√2

We want to find the length of the shorter leg:

⇒  x = n

⇒ 3√2 = n

Otras preguntas