Answer:
Step-by-step explanation:
Area of triangular pyramid = (1/3)*Base Area * height
[tex]= \dfrac{1}{3}*(\dfrac{1}{2}*b*h) *H[/tex]
1) b = 2 in ; h = 6 in and H = 5.8 in
[tex]Area= \dfrac{1}{3}*\dfrac{1}{2}*2*6*5.8 = 2*5.8 = 11.6 \ in^{2}[/tex]
2) b = 3 mi ; h = 4 mi and H = 4 mi
[tex]Area = \dfrac{1}{3}*\dfrac{1}{2}*3*4*4=2*4 = 8 \ mi^{2}[/tex]
3) b = 4 in ; h = 3 in & H = 11 in
[tex]Area=\dfrac{1}{3}*\dfrac{1}{2}*3*4*11=2*11 = 22 \ in^{2}[/tex]
4)b = 8 ft ; h = 15 ft ; H = 19ft
[tex]Area =\dfrac{1}{3}*\dfrac{1}{2}*8*15*19 = 380 \ ft^{2}[/tex]
5) base area = 4.5 mm^2 ; H = 4mm
[tex]Area = \dfrac{1}{3}*base \ area * height \\\\\\ =\dfrac{1}{3}*4.5 *4 \\\\= 1.5*4 = 6 \ mm^{2}[/tex]
