Answer:
[tex]w=\dfrac12I-1[/tex]
Or [tex]w=\dfrac12(I-2)[/tex]
(both are correct - just different ways of writing the equation)
Step-by-step explanation:
[tex]I = 2(w + 1)[/tex]
Expand the bracket:
[tex]\implies I = 2w + 2[/tex]
Subtract 2 from both sides:
[tex]\implies I - 2 = 2w + 2 - 2\\\\\implies I - 2 = 2w[/tex]
Divide both sides by 2:
[tex]\implies \dfrac{I-2}{2}=\dfrac{2w}{2}[/tex]
[tex]\implies w=\dfrac12I-1[/tex]
Solution:
Simplify the equation and solve for w.
The value of w is l/2 - 1 .
