Respuesta :

For solving these equation, it is important to isolate the variable to then solve it.

In this first equation,

3(4+x)=x+6

12+3x=x+6

12+2x=6

2x=-6

x=-3

to prove this, just substitute x value back into equation;

3(4-3)=-3+6

3(1)=3

3=3

Same for the next equations;

1+2x-x=x-5+x

1+x=2x-5

1=x-5

6=x

Then substitute this value back into equation;

1+2(6)-6=6-5+6

1+12-6= 12-5

7=7

Answer:

1. x = -3

2. x = 6

Step-by-step explanation:

3(4 + x) = 6 + x

Distribute

3 · 4 = 12

3 · x = 3x

12 + 3x = 6 + x

Subtract x on both sides.

3x - x = 2x

x - x = 0

Subtract 12 on both sides.

12 - 12 = 0

6 - 12 = -6

Divide 2 on both sides.

2x ÷ 2 = x

-6 ÷ 2 = -3

x = -3

Check: 3(4 - 3) = 6 - 3

12 - 9 = 3 TRUE

1 + 2x - x = x - 5 + x

Combine like terms.

x + 1 = 2x + -5

Subtract 2x on both sides.

−x + 1 = −5

Divide -1 on both sides.

-x ÷ -1

-6 ÷ -1

x = 6

Check: 1 + 2x - x = x - 5 + x

1 + 2(6) - 6 = 6 - 5 + 6

13 - 6 = 7 TRUE