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For solving these equation, it is important to isolate the variable to then solve it.
In this first equation,
3(4+x)=x+6
12+3x=x+6
12+2x=6
2x=-6
x=-3
to prove this, just substitute x value back into equation;
3(4-3)=-3+6
3(1)=3
3=3
Same for the next equations;
1+2x-x=x-5+x
1+x=2x-5
1=x-5
6=x
Then substitute this value back into equation;
1+2(6)-6=6-5+6
1+12-6= 12-5
7=7
Answer:
1. x = -3
2. x = 6
Step-by-step explanation:
3(4 + x) = 6 + x
Distribute
3 · 4 = 12
3 · x = 3x
12 + 3x = 6 + x
Subtract x on both sides.
3x - x = 2x
x - x = 0
Subtract 12 on both sides.
12 - 12 = 0
6 - 12 = -6
Divide 2 on both sides.
2x ÷ 2 = x
-6 ÷ 2 = -3
x = -3
Check: 3(4 - 3) = 6 - 3
12 - 9 = 3 TRUE
1 + 2x - x = x - 5 + x
Combine like terms.
x + 1 = 2x + -5
Subtract 2x on both sides.
−x + 1 = −5
Divide -1 on both sides.
-x ÷ -1
-6 ÷ -1
x = 6
Check: 1 + 2x - x = x - 5 + x
1 + 2(6) - 6 = 6 - 5 + 6
13 - 6 = 7 TRUE