Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction

How many distinct triangles can be formed for which m∠A = 75°, a = 2, and b = 3?

No triangles can be formed.
One triangle can be formed where angle B is about 15°.
One triangle can be formed where angle B is about 40°.
Two triangles can be formed where angle B is 40° or 140°.

Respuesta :

Answer:

D) Two triangles can be formed where angle B is 40° or 140°.

Step-by-step explanation:

The Ambiguous Case for the Law of Sines occurs when one uses it to determine missing measures of a triangle when given two sides and an angle opposite one of those angles (SSA). There are 6 cases:

Case 1: If ∠A is acute, and a < h, no such triangle exists

Case 2: If ∠A is acute, and a = h, one possible triangle exists

Case 3: If ∠A is acute, and a > b, one possible triangle exists.

Case 4: If ∠A is acute, and h < a < b, two possible triangles exist.

Case 5: If ∠A is obtuse, and a < b or a = b, no such triangle exists.

Case 6: If ∠A is obtuse, and a > b, one such triangle exists.

Here, we can see that ∠A is acute since 75°<90°

Also, we know that a < b since 2 < 3.

Thus, Case 4 applies here, which states "If ∠A is acute, and h < a < b, two possible triangles exist."

Thus, the last option is correct.

Read more:

http://jwilson.coe.uga.edu/EMT668/EMAT6680.2001/Mealor/EMAT%206700/law%20of%20sines/Law%20of%20Sines%20ambiguous%20case/lawofsinesambiguouscase.html

Answer:

It's D

Two triangles can be formed where angle B is 40° or 140°

Step-by-step explanation:

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