Answer:
[tex]y=x^2-20x+95[/tex]
Step-by-step explanation:
Write the equation in vertex form and evaluate
[tex]y=(x-h)^2+k\\\\y=(x-10)^2-5\\\\y=x^2-20x+100-5\\\\y=x^2-20x+95[/tex]
This is because the minimum (or maximum) of a quadratic curve is its vertex and [tex](h,k)[/tex] is the vertex in the formula I used
