Respuesta :

[tex]\\ \rm\hookrightarrow AE\cong FC[/tex]

So parallelogram BGAE and HDFC are equal.

  • GE=FC

And

  • BG=HD

As BG=HD

  • GC=AH

Hence

[tex]\\ \rm\hookrightarrow \triangle GEC\cong \triangle HFA(SSA)[/tex]