Answer:
No solution.
given:
- [tex]\sf 6x - 12y = 15[/tex]
- [tex]\sf 2x - 4y = 6[/tex]
make x the subject in equation 2:
[tex]\hookrightarrow \sf 2x = 6+4y[/tex]
[tex]\hookrightarrow \sf x = \dfrac{6+4y}{2}[/tex]
insert this in equation 1:
[tex]\hookrightarrow \sf 6(\dfrac{6+4y}{2}) - 12y = 15[/tex]
[tex]\hookrightarrow \sf 3(6+4y}) - 12y = 15[/tex]
[tex]\hookrightarrow \sf 18+12y - 12y = 15[/tex]
[tex]\hookrightarrow \sf 18 = 15[/tex]
[tex]\circle \bold \mathrm{\sf \The\:sides\:are\:not\:equal}[/tex]
y cancels out, thus no solution.
