Respuesta :

fieryanswererft

Answer:

[tex]\sf x= 55.7^\circ \:[/tex]

using tan rule:

[tex]\hookrightarrow \sf tan(x) = \dfrac{opposite}{adjacent}[/tex]

[tex]\hookrightarrow \sf tan(x) = \dfrac{22}{15}[/tex]

[tex]\hookrightarrow \sf x= tan^{-1}(\dfrac{22}{15} )[/tex]

[tex]\hookrightarrow \sf x = 55.7^\circ \:[/tex]

semsee45

Answer:

55.7° (nearest tenth)

Step-by-step explanation:

Use tan trig ratio:

[tex]\tan(\theta)=\dfrac{O}{A}[/tex]

where [tex]\theta[/tex] is the angle, O is the side opposite the angle and A is the side adjacent the angle.

Given:

  • [tex]\theta[/tex] = [tex]x[/tex]
  • O = 22
  • A = 15

[tex]\implies \tan(x)=\dfrac{22}{15}[/tex]

[tex]\implies x=\arctan\left(\dfrac{22}{15}\right)[/tex]

[tex]\implies x=55.7 \textdegree[/tex]

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