Answer:
[tex]\large\boxed{\sf x = 26}[/tex]
Step-by-step explanation:
A right angled triangle is given to us and we need to find out the value of x . We may use Pythagoras Theorem here as ,
[tex]\longrightarrow hypotenuse^2=perpendicular ^2+base^2 \\[/tex]
Here ,
- perpendicular = 24
- hypotenuse = x
- base = 10
On substituting the respective values , we have ;
[tex]\longrightarrow x^2 = 24^2+10^2 \\[/tex]
Solve the square ,
[tex]\longrightarrow x^2 = 576+100\\[/tex]
Add ,
[tex]\longrightarrow x^2 = 676 \\[/tex]
Put squareroot on both the sides ,
[tex]\longrightarrow x =\sqrt{676} \\[/tex]
Simplify ,
[tex]\longrightarrow \underline{\underline{ x =26}} \\[/tex]
