Using the binomial distribution, it is found that you could expect the product to be a multiple of 6 about 39 times.
For each trial, there are only two possible outcomes, either the result is a multiple of 6, or it is not. The result of each trial is independent of any other trial, hence the binomial distribution is used to solve this question.
It is the probability of exactly x successes on n repeated trials, with p probability of a success on each trial.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
In this problem:
Then, the expected value is given by:
[tex]E(X) = np = 100 \times \frac{14}{36} = 38.89[/tex]
Rounding up, you could expect the product to be a multiple of 6 about 39 times.
More can be learned about the binomial distribution at https://brainly.com/question/24863377