Answer:
they intersect each other at (6,0)
Explanation:
[tex]\sf x + 6y = 6[/tex]
[tex]\sf y = \frac{1}{3} x-2[/tex]
insert equation 2 into 1
[tex]\sf x + 6(\frac{1}{3} x-2) = 6[/tex]
[tex]\sf x + 2x - 12 = 6[/tex]
[tex]\sf 3x- 12 = 6[/tex]
[tex]\sf 3x = 6+12[/tex]
[tex]\sf 3x = 18[/tex]
[tex]\sf x = 6[/tex]
Find y:
[tex]\sf y = \frac{1}{3} (6)-2[/tex]
[tex]\sf y =2-2[/tex]
[tex]\sf y = 0[/tex]
Note: the blue line is [tex]\sf y = \frac{1}{3} x-2[/tex] and red line is [tex]\sf x + 6y = 6[/tex]
