Respuesta :

Esther

Answer:

a

Step-by-step explanation:

[tex]y\leq\frac{1}{2}x+2 \\\\1\leq \frac{1}{2}(0)+2\\\\1\leq 0+2\\\\1\leq 2[/tex]

This statement is true

Hope this helps!

Ver imagen Esther
MrRoyal

The linear inequality represented by the graph is y ≤ 1/2x + 2

How to determine the inequality?

From the graph, we have the following highlights:

  • The graph crosses the y-axis at c = 2
  • The graph is a less than or equal to graph

Next, we calculate the slope (m) using:

[tex]m = \frac{y_2 -y_1}{x_2 -x_1}[/tex]

Using the points on the graph, we have:

[tex]m = \frac{4 -2}{4 -0}[/tex]

Evaluate

m = 1/2

The first highlight implies that the y-intercept is 2.

So, the linear inequality is:

y ≤ mx + c

This gives

y ≤ 1/2x + 2

Hence, the linear inequality represented by the graph is y ≤ 1/2x + 2

Read more about linear inequality at:

https://brainly.com/question/18881247

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