Answer:-
[tex]\longrightarrow \sf h) \:\:\dfrac{2}{3},0.67,70\%,0.8[/tex]
Solution:-
Let us first write all the provided number in decimal
[tex]\quad\leadsto\sf \dfrac{2}{3}= 0.\bar{66}[/tex]
[tex]\quad\leadsto\sf 70 \% = \dfrac{70}{100}[/tex]
[tex]\quad\quad\quad\implies\sf 0.7 [/tex]
[tex]\quad\leadsto 0.67[/tex]
[tex]\quad\leadsto 0.8 [/tex]
Comparing all the numbers now -
[tex]\longrightarrow \sf 0.\bar{66}<0.67< 0.7<0.8 [/tex]
[tex]\longrightarrow\sf \dfrac{2}{3} <0.67<70\%<0.8 [/tex]
