The amount of paper needed to wrap the considered box which has dimension of 10 by 10 by 6 inches is 440 sq. inches
Let the three dimensions(height, length, width) be x, y,z units respectively.
The surface area of the cuboid is given by
[tex]S = 2(a\times b + b\times c + c\times a)[/tex]
A box is usually in shape of a cuboid.
For this case, its dimensions are 10 inches, 10 inches, and 6 inches.
The amount of wrapper we need is approx same as the area of its surface (assuming we're going to measure the paper needed in terms of its area).
Thus, we get:
Amount of the paper we need to wrap the considered box = surface area of that box = surface area of cuboid of dimension 10 inch by 10 inch by 6 inches = S (say), then:
[tex]S = 2(10\times 10+ 10\times 6 + 6\times 10)\\S = 440[/tex](in sq. inches)
Thus, the amount of paper needed to wrap the considered box which has dimension of 10 by 10 by 6 inches is 440 sq. inches
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